transposeMatrix.js No dry run

 /*Transpose Matrix

You are given m lists. Each list contains n elements. Represented as a matrix, this has m rows and n columns. Your task is to transpose the matrix and output the result.

Write a function with name transposeMatrix which takes a matrix as list of lists as input returns a transposed matrix as list of lists.

Matrix transpose

Given a matrix:

a b c d

e f g h

the transpose is:

a e

b f

c g

d h

Input

The first line contains m, denoting the number of lists

This is followed by m lines each containing n integers separated by space

Output

n lines should contain each row of the matrix, with the elements separated by a space

Example

Input:

3

1 2 3 4

5 6 7 8

9 10 11 12

Output:

1 5 9

2 6 10

3 7 11

4 8 12

You just have. to return transformed matrix as a list, printing is taken care of by the judge.

*/

let fs = require("fs");

let data = fs.readFileSync(0, 'utf-8');

let idx = 0;

data = data.split('\n');

function readLine() {

idx++;

return data[idx - 1].trim();

}

//////////////////////////////////////////////////////////////////////////////////////////////////////////////

let noOfRows = parseInt(readLine()); // 3

let matrix = []; // we will push the rows here afterwards

// This part is only to take the input

for (let i = 0; i < noOfRows; i++)

{

let arr = readLine().split(" ");

matrix.push(arr);

}

let noOfColoumns = matrix[0].length; // matrix['1', '2', '3', '4'].length i.e 4

let transposedMatrix = [];// we will push the transposed Matrix here after the operations

for (let j = 0; j < noOfColoumns; j++)

{

let temp = [];

for (let i = 0; i < noOfRows; i++)

{

temp.push(matrix[i][j]);

}

transposedMatrix.push(temp);

}

for (let i = 0; i < transposedMatrix.length; i++)

{

console.log(transposedMatrix[i].join(" "));

}

///////////////////////////////////////////////////////////////////////////////////////////////

TERMINAL: